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2022 WAEC Chemistry Question and Answers
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Number 4
a)
Step 1) Prepare a solution of calcium chloride: Dissolve calcium chloride (CaCl2) in water to create a calcium chloride solution. This step involves measuring the appropriate amount of calcium chloride and adding it to a container of distilled water while stirring until the compound is completely dissolved.
Step 2) Add a source of carbonate ions: Introduce a source of carbonate ions to the calcium chloride solution. This can be achieved by adding sodium carbonate (Na2CO3) or sodium bicarbonate (NaHCO3) to the solution. The carbonate ions from these compounds will react with the calcium ions in the solution, forming calcium carbonate.
Step 3) Precipitation of calcium carbonate: A white precipitate of calcium carbonate will form as a result of the reaction between the calcium ions and carbonate ions. The reaction can be written as follows:
Ca2+ (aq) + CO3^2- (aq) → CaCO3 (s)
The solid calcium carbonate will precipitate out of the solution.
Step 4) Filtration and washing: Use filtration to separate the solid calcium carbonate from the liquid solution. Set up a filter paper in a funnel and pour the mixture through it. The calcium carbonate will be retained on the filter paper while the liquid, containing any remaining calcium chloride and byproducts, passes through.
Step 5) Drying: After filtration, transfer the wet calcium carbonate onto a watch glass or a suitable container. Allow the solid to air dry or use gentle heat to remove any remaining moisture. The resulting dry solid is calcium trioxocarbonate (IV), commonly known as calcium carbonate.
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Number 5
ai)…
Reaction between Iron (Fe) and Dilute H2SO4:
Iron reacts with dilute sulfuric acid to form iron sulfate (FeSO4) and hydrogen gas (H2). The balanced chemical equation for this reaction is:
3Fe(s) + 4H2SO4(aq) -> 3FeSO4(aq) + 2H2(g) + 2H2O(l)
In this reaction, iron displaces hydrogen from the acid, resulting in the production of iron sulfate and hydrogen gas. The iron sulfate is soluble in water and remains in solution, while the hydrogen gas is released as a gas.
Reaction between Aluminum (Al) and Dilute H2SO4:
Aluminum reacts differently with dilute sulfuric acid due to the protective oxide layer that forms on its surface. The oxide layer prevents further reaction by acting as a barrier between the aluminum metal and the acid. However, the reaction can occur if the protective layer is disrupted or removed
2Al(s) + 3H2SO4(aq) -> Al2(SO4)3(aq) + 3H2(g)
In this reaction, aluminum sulfate (Al2(SO4)3) and hydrogen gas are produced. The aluminum sulfate formed is soluble in water and remains in solution, while the hydrogen gas is liberated as a gas.
WAEC Chemistry 2023 Question Solutions
1. Be very well prepared for the Chemistry examinations:
2. Use the recommended texts for Chemistry
3. Be confident in yourself
2. Ask God for guidance as you pray about your Chemistry exams:
3. Arrive early at the location of the Chemistry exams:
4. Carefully follow the guidelines on the Chemistry exam paper:
5. Use the WAEC syllabus
WAEC Chemistry 2023 Questions Exam Time
Wednesday 24th May 2023
===================
Chemistry
8:30 – 11:30 am
2023 WAEC Chemistry Expo Answers
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(1a)
A transition element, also known as a transition metal, is an element that belongs to the d-block of the periodic table.
(1b)
(i) Element B (2:8:2)
(ii) Element C (2:8:1)
(1c)
The increase in the first ionization energies across a period is mainly due to the increasing effective nuclear charge and decreasing atomic radius. The stronger pull from the increasing nuclear charge and the closer proximity of the electrons to the nucleus make it harder to remove an electron, leading to higher ionization energies.
1di)
Two examples of aliphatic compounds are:
A. Ethane (C2H6): Ethane is a saturated hydrocarbon belonging to the alkane family. It consists of a straight chain of two carbon atoms bonded to each other, with six hydrogen atoms attached to the carbons.
B. Butanol (C4H10O): Butanol is an alcohol with a four-carbon straight chain. It has the chemical formula C4H10O and exists in four isomeric forms: n-butanol (normal butanol), sec-butanol (secondary butanol), isobutanol (isopropyl alcohol), and tert-butanol (tert-butyl alcohol)
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WAEC Chemistry Essay Questions and Answers 2023/2024
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